Ex. No.:
12
|
THREE
ADDRESS CODE GENERATION
|
AIM :
To write a
C program to generate a three address code for a given expression.
ALGORITHM:
Step1: Begin the program
Step2 : The expression is read from
the file using a file pointer
Step3 : Each string is read and the
total no. of strings in the file is calculated.
Step4: Each string is compared with
an operator; if any operator is seen then the previous string and next string
are concatenated and stored in a first temporary value and the three address
code expression is printed
Step5 : Suppose if another operand
is seen then the first temporary value is concatenated to the next string using
the operator and the expression is printed.
Step6 : The final temporary value
is replaced to the left operand value.
Step7 : End the program.
PROGRAM: //program for three address code
generation
#include<stdio.h>
#include<conio.h>
#include<stdlib.h>
#include<string.h>
struct
three
{
char data[10],temp[7];
}s[30];
void main()
{
char d1[7],d2[7]="t";
int i=0,j=1,len=0;
FILE *f1,*f2;
clrscr();
f1=fopen("sum.txt","r");
f2=fopen("out.txt","w");
while(fscanf(f1,"%s",s[len].data)!=EOF)
len++;
itoa(j,d1,7);
strcat(d2,d1);
strcpy(s[j].temp,d2);
strcpy(d1,"");
strcpy(d2,"t");
if(!strcmp(s[3].data,"+"))
{
fprintf(f2,"%s=%s+%s",s[j].temp,s[i+2].data,s[i+4].data);
j++;
}
else
if(!strcmp(s[3].data,"-"))
{
fprintf(f2,"%s=%s-%s",s[j].temp,s[i+2].data,s[i+4].data);
j++;
}
for(i=4;i<len-2;i+=2)
{
itoa(j,d1,7);
strcat(d2,d1);
strcpy(s[j].temp,d2);
if(!strcmp(s[i+1].data,"+"))
fprintf(f2,"\n%s=%s+%s",s[j].temp,s[j-1].temp,s[i+2].data);
else
if(!strcmp(s[i+1].data,"-"))
fprintf(f2,"\n%s=%s-%s",s[j].temp,s[j-1].temp,s[i+2].data);
strcpy(d1,"");
strcpy(d2,"t");
j++;
}
fprintf(f2,"\n%s=%s",s[0].data,s[j-1].temp);
fclose(f1);
fclose(f2);
getch();
}
Input: sum.txt
out = in1 + in2 + in3 - in4
Output :
out.txt
t1=in1+in2
t2=t1+in3
t3=t2-in4
out=t3
RESULT:
Thus a C
program to generate a three address code for a given expression is written,
executed and the output is verified.
Ex. No.:
13
|
GENERATION OF ASSEMBLY LANGUAGE
INSTRUCTION FROM THREE ADDRESS CODE
|
AIM :
To write a
C program to generate an assembly language instruction from three address code.
ALGORITHM:
Step1 : Begin the program
Step2 : The file containing the three address code is given
as input to this program
Step3 : Each string is read from the file
Step4 : In an expression the string the left of the operator
is printed with the ‘LDA’ string.
Step5 : Next if the operator is ‘+’ then ‘ADO ’ is printed else ‘SUB’ is printed
followed by the string to the right of
the operator.
Step6 : Then ‘STA’ string is printed followed by the string
value left of the ‘=’ operator
Step7 : .End of the program
PROGRAM: //GENERATION
OF ASSEMBLY LANGUAGE INSTRUCTION FROM THREE ADDRESS CODE
#include<stdio.h>
#include<conio.h>
#include<string.h>
struct
three
{
char
data[10],temp[7];
}s[30];
void
main()
{
char *d1,*d2;
int i=0,len=0;
FILE *f1,*f2;
clrscr();
f1=fopen("exe1.txt","r");
f2=fopen("exe2.txt","w");
while(fscanf(f1,"%s",s[len].data)!=EOF)
len++;
for(i=0;i<=len;i++)
{
if(!strcmp(s[i].data,"="))
{
fprintf(f2,"\nLDA\t%s",s[i+1].data);
if(!strcmp(s[i+2].data,"+"))
fprintf(f2,"\nADD\t%s",s[i+3].data);
if(!strcmp(s[i+2].data,"-"))
fprintf(f2,"\nSUB\t%s",s[i+3].data);
fprintf(f2,"\nSTA\t%s",s[i-1].data);
}
}
fclose(f1);
fclose(f2);
getch();
}
Input: exe1.txt
t1 = in1 + in2
t2 = t1 + in3
t3 = t2 - in4
out
= t3
Output: exe2.txt
LDA in1
ADD in2
STA t1
LDA t1
ADD in3
STA t2
LDA t2
SUB in4
STA t3
LDA t3
STA out
RESULT:
Thus a C program
to generate a assembly language instruction from three address code is written,
executed and the output is verified.
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