NUMBER OF DIGITS IN AN INTEGER----- unix lab

NUMBER OF DIGITS IN AN INTEGER

AIM:

            To count the number of digits in an integer, using Shell Programming.

ALGORITHM:

Step 1: Start

Step 2: Read the value of ‘a’

Step 3: Initialize the value of c as 0

Step 4: When the value of ‘a’ is not equal to 0, solve n=a %10.

Step 5: If the value of ‘n’ is not equal to 0, solve c=c + 1(increment)

Step 6: End if condition

Step 7: Solve the expression “a=a / 10”

Step 8: Repeat steps 4 to 7 until ‘a’ is equal to 0

Step 9: Print the value of c as the number of digits in an integer.

Step 10: Stop.

SHELL PROGRAM:

echo "Enter a Number"

read a

c=0

while [ $a -ne 0 ]

do

n=`expr $a % 10`

if [ $n -ne 0 ]

then

c=`expr $c + 1`

fi

a=`expr $a / 10`

done

echo "The Number of Digits in the Integer is $c"

SAMPLE OUTPUT:

Enter a Number

123456789

The Number of Digits in the Integer is 9

RESULT:     

            Thus the Shell Program to calculate the number of digits of an integer was executed and the output was verified.