Predict the output or error(s) for the following
{
int i=-1,j=-1,k=0,l=2,m;
m=i++&&j++&&k++||l++;
printf("%d %d %d %d %d",i,j,k,l,m);
}
Answer:
0 0 1 3 1
Explanation :
Logical operations always give a result of 1 or 0 . And also the logical AND (&&)
operator has higher priority over the logical OR (||) operator. So the
expression ‘i++ && j++ && k++’ is executed first. The result of this expression is
0 (-1 && -1 && 0 = 0). Now the expression is 0 || 2 which evaluates to 1
(because OR operator always gives 1 except for ‘0 || 0’ combination- for which it
gives 0). So the value of m is 1. The values of other variables are also incremented
by 1.
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